At the moment there is no way to measure the properties of a 400 Mbps video made by GH5. But perhaps we could try to model that using the already available video formats. I've recorded a 24p 4:2:2/10 4K (3840x2160) at 150 Mbps according to camera settings) video in Standard color profile that duration of 00:01:00.50 (1451 video frames). The stats for the video stream are: frame count min_size avg_size max_size -------- ----- ---------- ---------- ---------- overall 1451 180896 765054 2752159 I-frames 121 1674497 2551558 2752159 P-frames 1330 180896 602523 783379 B-frames 0 0 0 0 As you can see, the average size of I-frame is 2,551,558 bytes or 20,412,464 bits (2.46 bits per pixel). Let's assume that ALL-I codec will have same settings as used now for I-frames. That would mean that for the same video capturing settings ALL-I codec should be outputting 2,551,558 * 24 = 61,237,392 bytes or 489,899,136 bits, which in turn is 489 Mbps or 467 Mbps (depending whether M in Mbps is 1000 or 1024). If we turn around the calculations and see how big is the size of the frame in ALL-I 400 Mbps stream of the same framerate (24 fps), we would get 400,000,000 / 24 = 16,666,666 bits (2.01 bits per pixel) or 419,430,400 / 24 = 17,476,266 bits (2.11 bits per pixel) - again, depending on the meaning of M in Mbps. The bits-per-pixel wise ALL-I 400 Mbps only reaches 82% or 86% of the IPB 150 Mbps level (depending on the meaning of M in Mbps). To reiterate, for subjects with no rapid movements in frame, IPB codec provides better IQ compared to the same bitrate ALL-I video. Please spread the word!